Simplify code to get path and filename

This commit is contained in:
croneter 2019-03-17 11:30:44 +01:00
parent 98975ff23d
commit db0f7f283e

View file

@ -22,12 +22,9 @@ def kodiid_from_filename(path, kodi_type=None, db_type=None):
"""
kodi_id = None
path = utils.try_decode(path)
try:
filename = path.rsplit('/', 1)[1]
path = path.rsplit('/', 1)[0] + '/'
except IndexError:
filename = path.rsplit('\\', 1)[1]
path = path.rsplit('\\', 1)[0] + '\\'
path, filename = path_ops.path.split(path)
# Make sure path ends in either '/' or '\'
path = path_ops.path.join(path, '')
if kodi_type == v.KODI_TYPE_SONG or db_type == 'music':
with KodiMusicDB(lock=False) as kodidb:
try: